Introduction - What are A.C. Circuits?
A. C. Circuits are electrical circuits in which the source of electricity
generates an Alternating Current. This generator produces a sinusoidal
voltage (emf) with a corresponding sinusoidal current through a close
circuit. These voltages and currents are usually generated by a
rotating coil in a constant magnetic field with a constant angular velocity
ω which induces in the coil an instantaneous voltage v expressed
by the following equation:
v = Vm sin ωt, (1)
where Vm is the maximum voltage produced by the
ac generator. The angular velocity is related to the frequency f
of the wave by the equation
ω = 2πf = 2π/T, (2)
where T is the period of the wave, which is the time of one cycle of the
sinusoidal voltage wave. The ac current exhibits a similar time variation.
This kind of circuit is called alternating because the voltage and current in
the circuit periodically reveses its polarity and direction, respectively.
A.C. Circuit with Resistance only.
Consider the simple ac circuit which consists of a resistor and an ac
generator. At any instant, the algebraic sum of potential increases and
decreases around the close loop of the circuit must be zero (kirchhoff's
loop equation). Therefore, v - vR = 0, or
v = vR =
Vm sin ωt, (3)
where vR is the instantaneous voltage drop across the
resistor. Therefore, the instantaneous current in the resistor is equal to
iR = vR/R =
(Vm/R) sin ωt =
Im sin ωt, (4)
where R is the resistance of the resistor and Im is
the maximum current in the circuit, given by the equation
Im = Vm/R. (5)
From equations (3) and (4) it is clear that Vm =
ImR and the instantaneous
voltage drop across the resistor is
vR =
ImR sin ωt. (6)
Since vR and iR both vary sinsusoidal as sin ωt and reach their maximum values at the same time, they are said to be in phase; they also reach their maximum and zero values at the same instant. Very often this phase relationship between the voltage and current is represented by a phasor diagram. In these diagrams, the alternating quantities is represented by an arrow, called a phasor, that rotates in a counterclockwise direction. The length of the arrow corresponds to the maximum value of the alternating quantity, and the projection of the arrow on the vertical axis gives the instantaneous value of the quantity. In the case of a single-loop resistive circuit, the current and voltage phasors lie along the same line, since vR and iR are in phase with each other. Note that although arrows are used for the phasors they are not vectors in the ordinary sense, because they do not represent a direction in space.
Note that the average value of the current over one cycle is zero. That is,
the current is maintained in the same direction (say, the positive direction)
over the same amount of time and at the same magnitude as in the opposite
direction (the negative direction). Note that the direction of the current
has no effect upon the resistor. Although the temperature in the resistor
depends on the magnitude of the current, it does not depend on its direction.
The rate at which electrical energy is converted into heat energy, which is
called the power P, is given by
P = i2R, (7)
where i is the instantaneous current in the resistor. Since the heating
effect of a electrical current is proportional to the square of the current,
it makes no difference whether the current is direct or alternating; that is,
whether the sign of the current is positive or negative. However, the
heating effect produced by an alternating current having a maximum value
Im is not the same as that produced by a direct current of
the same value. The alternating current is at its maximum value for only a
brief instant during a cycle. What is important for the heating effect in an
ac circuit is the average value of the current that is called the rms
current. The term rms refers to the root mean square method of
determining the average by taking the square root of the average of the square
of the current. Since I2 varies as
sin2 ωt,
it can be shown that the average value of I2 is
(1/2)Im2.
Note first that the graph of
cos2 ωt versus time is identical to the
graph of sin2 ωt versus time, except that the
graph is shifted on the time axis. Thus the time average of
sin2 ωt is equal to the time average of
cos2 ωt when taken over one or more complete
cycles. That is,
(sin2 ωt)av =
(cos2 ωt)av.
Using the trigonometic identity,
sin2 θ + cos2 θ = 1, we get
(sin2 ωt)av +
(cos2 ωt)av =
2(sin2 ωt)av = 1, or
(sin2 ωt)av = 1/2.
Substituting this into the following equation, after taking the average of
i2 =
(Im)2 sin2 ωt,
we get
(i2)av =
(Im)2
(sin2 ωt)av =
Im2(1/2).
Taking the square root, we get
Irms = Im/√2.
Therefore, the rms current
Irms is related to the maximum value of the alternating
current Im, as
Irms = Im/√2 =
0.707 Im. (8)
Thus the average power dissipated in a resistor carrying an alternating
current is
Pav =
Irms2R. (9)
Alternating voltages should also be discussed in terms of rms voltages,
and the relationship is the same as for rms currents; that is,
rms voltage, Vrms, is related to the maximum value
of the voltage, Vm, as
Vrms = Vm/√2 =
0.707 Vm. (10)
In this paper the rms values shall be used when discussing alternating
currents and voltages. One reason for doing this is that is that ac ammeters
and voltmeters are designed to measure rms values. Another reason is
that many of equations of ac circuits are similar to those in dc circuits,
if they are written with rms values.
A. C. Circuit with Induction only.
Consider now an ac circuit consisting of only an inductor connected to the
terminals of an ac generator. The instantaneous voltage drop across the
inductor is vL and applying Kirchhoff's loop rule to the
circuit we get v + vL = 0, or
v - L(di/dt) = 0.
Rearranging this equation, and substituting for
v = Vmsin ωt, we get
L(di/dt) =
Vm sin ωt. (11)
Solving this equation for di, we get
di = (Vm/L) sin ωt dt,
and integrating this equation gives the current as a function of time:
iL =
(Vm/L)∫(sin ωt dt) =
-(Vm/ωL)
cos ωt. (12)
Using the trigonometric identity cos ωt =
-sin (ωt - π/2), equation (12) can be written
iL = (Vm/ωL)
sin(ωt - π/2). (13)
Comparing this equation with equation (11) clearly shows that the current
is out of phase with the voltage by π/2, or 90°. A plot of the voltage
and current versus time shows that the voltage reaches its maximum value at
a time that is one quarter of its period before the current reaches its
maximum value. Thus we see that for a sinusoidal applied voltage, the
current always lags behind the voltage across the inductor by 90°.
The explanation of this is that since the voltage across the inductor is
proportional to di/dt, the value of vL
is largest when the current is changing most rapidly. Since i
versus t is a sinusoidal curve, di/dt (the slope) is
a maximum when the curve goes through zero. This shows that
vL reaches its maximum value when the current is zero.
From equation (12) we see that the maximum current Im is
Im = (Vm/ωL) =
Vm/XL, (14)
where the quantity XL is called the
inductive reactance and is defined as
XL = ωL. (15)
The rms current is given by equations similar to equation (14) with
Vm replaced by Vrms. The term
reactance is used so that it is not confused with resistance.
In a resistive circuit, i and v are always in phase, whereas
i lags behind v by 90° in a purely inductive circuit.
Using equations (11) and (14), the instantaneous voltage drop across the
inductor can be found by following equation:
vL = Vm sin ωt =
ImXL
sin ωt. (16)
This equation can be considered as Ohm's law for an inductive circuit. That is,
Vm =
ImXL. (17)
Note that the reactance of an inductor increases with increasing frequency.
This is because at higher frequencies, the current must change more rapidly,
which in turn causes an increase in the induced emf associated with a given
maximum current.
Inductance and Resistance.
An inductor cannot be entirely without resistance since resistance is an
inherent property of the conductors in the coil of wires in the inductor.
Thus the resistance of the inductor must be lumped with any resistance in
series with the inductor. The same current will be present in all parts of a
series circuit. Thus the circuit current is used as reference to show the phase
between current and voltages in the resistance and inductance. The voltage
across the resistance is in phase with the circuit current. The voltage
across the inductance leads the circuit current by 90°. The voltage
across the series combination of R and L will then lead the
circuit current by some angle between 0° and 90°.
Because of the difference of phase angles of the voltages across the resistance and inductance, the voltages VR and VL cannot be added algebraically but must be added vectorally to give the circuit voltage V. That is, the voltage V across the whole external circuit is the resultant, or vector sum, of the voltages VL and VR. The phase angle φ will have a positive value less than 90°.
The potential drop across the resistance in series with the inductance is
equal to the product IR, where R is the common resistance to
the current in the external circuit. The inductance as a consequence of its
opposition to the current in the circuit has a voltage difference across it.
The oppositon is non-resistive because no power is dissipated in the inductance
and thus is called reactance, XL. This inductive
reactance XL is the ratio of the effective value of
the potential, VL, to the effective value of the current,
I; that is,
XL = VL/I.
Thus the voltage drop across the inductance VL is equal to
the product, IXL.
The inductive reactance of a coil is directly proportional to the inductance
L and to the frequency f of the current in the circuit. This
is because the rate of change of a given current increases with frequency.
And the larger the inductance L, the larger the opposition to the
change of the current at a given frequency. That is,
XL = 2πfL = ωL,
where ω is called the angular velocity of the frequency and is equal to
2πf. The frequency is measured in hertz and inductance L
in henrys, and the inductive reactance XL in ohms. The
2π is the constant of proportionality between the inductive reactance and
the product of the frequency and inductance.
The vector sum of the IXL and the IR is equal to the voltage, V, applied to the external circuit. This voltage or potential difference across the external circuit is the product of the circuit current, I, and the combination of the effect of the inductive reactance, XL, and the resistance, R, in the load. This combination or joint effect of the reactance and resistance in an ac circuit is called impedance, Z. It is measured in ohms. Hence, V is equal to the product IZ. If each voltage VL, VR and V are divided by the current I, then VL/I = IXL/I yields the inductive reactance XL and VR/I = IR/I yields the resistance R, and V/I = IZ/I yields the impedance Z.
The relationship between the inductive reactance
XL, resistance R and the impedance Z can
be represented by a right triangle that is called a impedance diagram.
In this right triangle that is called an impedance diagram, the short sides
or legs represent XL and R and the long side or
hypotenuse of the right triangle represents the impedance Z. The
acute angle opposite the side that represents the inductive reactance
XL represents the phase angle φ. The tangent of the
phase angle φ is defined as the ratio of the side of the right triangle
opposite to φ to the side adjacent to φ in the right triangle. Thus,
XL/R = tan φ
This equation gives the ratio XL/R as a function of
φ. It also enables us to find φ as a function of
XL/R.
That is, φ is an angle whose tangent is XL/R.
This phrase, "φ is an angle whose tangent is XL/R"
expresses what is called in trigonometry the inverse function to
the tangent. The inverse function of the tangent is called the "arc tangent".
The symbol for arc tangent is arc tan or tan-1.
The inverse function to the tangent of the phase angle in the above equation
is commonly written:
φ = arc tan(XL/R) =
tan-1(XL/R).
In general, the impedance Z has a magnitude equal to
√(R2 + X2)
and a phase angle φ (the direction of Z relative to R),
whose tangent is X/R. This can be written in the polar form
Z∠φ as
Z =
√(R2 + X2)∠X/R.
When the reactance is inductive, that is,
X = XL, and φ is a positive angle whose tangent
is XL, the magnitude of the impedance is given by the
expression:
√(R2 + XL2).
In this polar expression, √(R2 + X2)
is the magnitude and the symbol ∠ is interpreted to mean
"at an angle of —°".
Ohm's law for dc circuits can be generalized into a form that applies to
ac circuits. For the entire ac circuit,
E = IZ,
and for external circuit,
V = IZ.
The relation between the current I in the external circuit and the
voltage V across it may be written as
I = VY,
where Y is called admitance and is defined as the reciprocal
of impedance, that is,
Y = 1/Z,
so that,
V = IZ = I/Y.
Admittance is measured in mhos ("ohm" spelled backwards).
A. C. Circuit with Capitance only.
Let us now consider an ac circuit that consists of a capacitor connected
across the terminals of an ac generator. The instantaneous voltage drop
across the capacitor is vC and applying Kirchhoff's loop
rule to the circuit we get v - vC = 0, or
v = vC =
Vm sin ωt. (18)
From the definition of capacitance, vC = Q/C,
which when substituted in equation (18), we get
Q =
CVm sin ωt. (20)
And since i = dQ/dt, differentiating equation (20) gives
the instantaneous current:
iC = dQ/dt =
ωCVm cos ωt. (21)
Again, we see that the current is not in phase with the voltage drop across
the capacitor, given by equation (18). Using the trigonometric identity
cos ωt = sin (ωt + π/2),
equation (21) can be written
iC = ωCVm
sin(ωt + π/2). (22)
Comparing this equation with equation (18), we see that the current is 90°
out of phase with the voltage across the capacitor. A plot of the voltage
and current versus time shows that the current reaches its maximum value at
a time that is one quarter of its cycle sooner the voltage reaches its
maximum value. Thus we see that for a sinusoidal applied emf, the
current always leads the voltage across the capacitor by 90°.
From equation (22), we see that the maximum current in the circuit is
given by
Im = ωCVm
(Vm/XC), (23)
where the quantity XC is called the
capacitive reactance and is defined as
XC = 1/ωC. (24)
The rms current given by equations similar to equation (23) with
Vm is replaced by Vrms.
Using equations (18) and (24), the instantaneous voltage drop across the
capacitor can be found by following equation:
vC = Vm sin ωt =
ImXC
sin ωt. (25)
This equation can be considered as Ohm's law for an capacitive circuit.
That is,
Vm =
ImXC. (26)
The unit for XC is also the ohm. As the frequency of the
circuit increases, capacitive reactance decreases. For a given maximum
applied voltage, Vm, the current increases as the frequency
increases. As the frequency approaches zero, the capacitive reactance
approaches infinity. Therefore, the current approaches zero. This makes
sense since the circuit approaches dc conditions as ω → 0.
Of course, a capacitor passes no current under steady-state conditions.
Capactance and Resistance.
In an ac circuit the opposition to the current due to capacitance is
nonresistive since no power is dissipated in the capacitor. This nonresistive
opposition is called capactive reactance. The symbol for capacitive
reactance is XC and it is measured in ohms.
The inherent resistance in any real circuit containing capacitance can be represented as in series with XC. The potential difference V across the external circuit is the vector sum of VC and VR; the series current is used as the reference. There is, of course, no electrons flowing through the capacitance; the capacitor is alternately charged, first in one sense and then in the other, as the changing current alternates. The phase angle φ is negative, which is characteristic of a lagging voltage.
The corresponding phasor diagram for a capacitve circuit can be produced by dividing each voltage phasor by the circuit current. Just as VC is negative with respect to VL, so XC is plotted opposite to the direction of XL.
Because VC = Q/C, the higher the capactance
the lower is the potential difference VC that develops
across the capacitor for a given charge Q. Thus the capacitive
reactance in an ac circuit varies inversely with the capacitance in the
circuit. As the frequency of a changing current is increased, a shorter
time is available during each current cycle for the capacitor to charge and
discharge. Smaller changes in voltage occur across the capacitor. Hence
the capacitive reactance to the circuit current varies inversely with the
current frequency. That is,
XC = 1/(2πfC),
where f is measured in hertz, C in farads, the capacitance
XC is measured in ohms.
The impedance of a circuit, Z, containing capacitance and resistance in series, has a magnitude equal to √(R2 + Xc2) and a phase angle, φ, whose tangent is -XC/R.
When a capacitor in a dc circuit is charged to the applied voltage, it acts
as an open switch and the current in the circuit is zero. While the capacitor
remains in fully charged state, the capacitive reactance in the circuit is
infinitely high regardless of the value of C. A capacitor in an ac
circuit has a very different effect on the alternating current and voltage.
Electrons flow in one direction during on half-cycle, charging the capacitor
in one sense. The electron flow is in the opposite direction during the other
half-cycle, reversing the charge on the capacitor. If the current has very
low frequency, the capacitive reactance is very large, since
XC = 1/(2πfC).
This large reactance effectively limits the circuit current. At higher
frequencies, less change occurs in the charge on the capacitor during each
half-cycle and the reactive opposition to the circuit current is lower.
At extremely high frequencies, the change in capacitor charge becomes
negligible and the capacitive reactance in the circuit becomes negligible
factor in limiting the circuit current. The larger the capacitor in the
circuit, the more rapidly the capacitive reactance decreases with increasing
frequency. Note that in the above equation for XC, the
magnitude of XC varies inversely with frequency f,
with capacitance C, and with their product fC.
The RLC Series Circuit.
In the previous section, we have examined the effects that an inductor, a
capacitor, and a resistor have when they are placed separately across
the terminals of an ac voltage source. Now we shall consider what happens
when they are placed in combinations across the ac source. This is a more
realistic situation, because resistance always occurs in the external
ciruit and/or in the internal circuit of the ac source.
We shall consider the circuit in which the resistor, inductor, and capacitor
are connected in series across an ac-voltage source. Let us assume that
the sinsusoidal current in the circuit has reached a steady-state value.
As before, the applied voltage is assumed to vary sinusoidally with time.
We will assumed that the applied voltage is
v = Vm sin ωt,
while the current varies as
i = Im sin(ωt - φ),
where the quantity φ is called the phase angle between the current
and the applied voltage. Our problem is to determine φ and
Im.
Note that since the circuit elements are in series, the current everywhere
in the circuit must be same at any instant. That is, the ac current at all
points in a series circuit must be the same amplitude and phase. The voltage
across the different elements will have different amplitude and phases.
In particular, the voltage across the inductor leads the current by 90°,
and the voltage across the capacitor lags behind the current by 90°.
Thus the instantaneous voltages across the three elements with their
phase angles are
vR = ImR sin ωt =
VR sin ωt, (27)
vL =
ImXL
sin(ωt + π/2) =
VL cos ωt, (28)
vC =
ImXC
sin(ωt - π/2) =
-VC cos ωt, (29)
where VR, VL, and VC
are the maximum voltages across each element, given by
VR = ImR, (30)
VL = ImXL, (31)
VC = ImXC, (32)
so that the instantaneous voltage across the three elements is equal to the sum
of the instantaneous voltage drops across the three circuit elements, R,
L, and C, that is,
v = vR + vL +
vC. (33)
Assuming a sinusoidal impressed voltage, we can write equation (33) as
Vm sin (ωt - φ) =
Ri + L(di/dt + q/C),
or, since i = dq/dt, we get
Vm sin (ωt - φ) =
L(d2q/dt2) +
R(dq/dt) +
q/C,
The solution of this linear second order differential equation can be
found similar to the solution of an equivalent differential equation for a
forced mechanical oscillator. In the solution q is a function of time,
and knowing q as a function of time, then the current as a function of
time can be found.
Although this analytical approach can be used, it is simpler to obtain the
sum by examining the rotating phasor diagram of maximum voltages. Because the
current in each element is the same at any instant, the diagram of each phasor
can be combined into a single diagram, where a single phasor
Im is used to represent the common current in each element.
To obtain the vector sum of these voltages, the diagram must be redrawn as a
right triangle where the phasor of the resistance element VR,
which is in phase with the current phasor Im, is drawn along
the horizontal leg and the phasors for VL and
VC are drawn along the vertical leg of the right triangle.
Since the voltage phasor VL leads the current phasor
Im by 90° and VC lags behind
the current phasor by 90°, they can be drawn on the phasor diagram
along the same vertial line. And since VL and
VC are thus always along the same verticle line but
in opposite directions, they can be combined in in a single phasor having
the following magnitude:
VX = VL - VC,
which is perpendicular to the phasor VR. This single phasor
VX is represented as along the other leg of the right
triangle. Thus the total voltage Vm is the hypotenuse of
the right triangle, whose sides are VR and
VX = VL - VC,
and makes an phase angle φ with the current phasor Im.
Using the pythagorean theorem, we get
Vm = √[VR2 +
(VL - VC)2] =
√[(ImR)2 +
(ImXL -
ImXC)2], or
Vm =
Im √[R2 +
(XL - XC)2], (34)
where inductive reactance XL = ωL and
capactive reactance XC = 1/ωC.
Therefore, solving equation (34) for Im,
the maximum current is
Im = Vm/Z,
where Z is called the impedance of the circuit and is defined as
Z = √[R2 +
(XL - XC)2] =
√[R2 + X2], (35)
where X = XL - XC is called
the total reactance of the circuit and may be either positive or
negative (X2 is always positive).
Therefore, equation (34) can be written as
Vm = ImZ. (36)
Impediance also is measured in ohms. Equation (36) may be regarded as
a generalization of Ohm's law as applied to an ac circuit. Note that the
current in the circuit depends upon the resistance, the inductance, the
capacitance, and the frequency since the reactances are frequency dependent.
By removing the common factor Im from the our redrawn phasor
diagram, we can construct an impedance triangle. From the redrawn phasor
diagram, we see that the phase angle φ between the current and voltage is
tan φ =
(VL - VC)/VR =
(IXL - IXC)/IR =
X/R,
or
tan φ =
(XL - XC)/R =
X/R. (37)
For example, when XL > XC (which
occurs at high frequencies), the phase angle is positive, signifying that
the current lags behind the applied voltage. On the othe hand,
XL < XC, the phase angle is negative,
signifying that the current leads the applied voltage. Finally, when
XL = XC the phase angle is zero. In this
case, the ac impedance equals the resistance and the current has its
maximum value, given by Vm/R. The frequency at
which this occurs, is called the resonance frequency.
Series Resonance.
In a series RLC circuit the voltages across an inductance and a capacitance
are of opposite polarity. If XL is larger than
XC, the circuit is inductive and the voltage across the
circuit leads the current. If XC is the larger reactance,
the circuit is capacitive and the circuit voltage lags behind the current.
In either instance, the impedance, Z, has a magnitude
√[R2 +
(XL - XC)2]
and a phase angle, φ, whose tangent is
(XL - XC)/R.
The frequency of the ac voltage applied to a series circuit with fixed
values of L, R, and C determines the reactance of
the circuit. The reactance of the circuit will be inductive over a range
of high frequencies and capacitive over a range of lower frequencies.
At some intermediate frequency, the inductive and capacitive reactances
will be equal; then the reactance of the circuit
X = XL - XC, equals zero.
At this frequency, the impedance, Z, is at its minimum value for
the series circuit. It is equal to the inherent circuit resistance,
R. As is true of all circuits with pure ohmic resistance, the
voltage across the circuit and the current in the circuit will be in phase.
This special circuit condition is known as series resonance. The
frequency at which resonance occurs is called the resonant frequency,
f0. Series resonance is a condition in which
the impedance of an RLC series circuit is equal to the circuit resistance,
and the voltage across the circuit is in phase with circuit current.
That is, at resonance, Z = R since
XL = XC.
To find the resonant frequency, f0, solve this last relation
for ω0, since XL = ωL and
XC = 1/ωC. That is,
ω0L = 1/(ω0C), or
ω02 = 1/(LC), or
ω0 = 1/√(LC).
Since ω = 2πf, we get
f0 = 1/[2π√(LC)].
At frequencies below the resonance point, the series circuit is capacitive, performing as one with an XC and R in series. At the resonant frequency, f0, the circuit performs as one containing pure resistance. Above the resonant frequency, it is inductive, performing as one with an XL and R in series.
The current in a series RLC circuit reaches its maximum value when the frequency of the generator reaches ω0; that is, when the "driving" frequency matches the resonance frequency.
Selectivity in Series Resonance.
A resonant circuit responds to impressed voltages of different frequencies
in a selective manner. The circuit presents a high impedance to a signal
voltage of a frequency above or below the resonant frequency of circuit.
The resulting current is correspondingly small. The same circuit presents
a low impedance, consisting of the circuit resistance, to a signal voltage
at the resonant frequency. The current is correspondingly large.
The principle of resonance is widely used in electronic as a "tuned" circuit
to select a particular frequency from a band of frequencies that may be
impressed on a circuit. A tuned circuit thus discrimates among signl voltages
of different frequencies. This property of signal discrimation is known as
the circuit's selectivity. The lower the resistance of the series
circuit, the higher the resonant current and more sharply selective is the
circuit. The usual circuits used for signal discrimation consists of an
inductor and a capacitor. The only resistance is that inherent in the
circuit, which is almost all entirely the resistance of the coil of the
inductor. The characteristics of the series resonant circuit depends
primarly on the ratio of the inductive reactance to the circuit resistance,
XL/R. That is,
Q0 ≈ ω0L/R.
This ratio is called the Q, or quality factor, of the circuit. It is
essentially a design characteristic of the inductor. The higher the
Q, the more sharply selective is the series resonant circuit.
Resonant circuits can be tuned over a range of frequencies by making either the inductance or the capacitance variable. The position of a powdered-iron core in a coil can be varied to change the coil's inductance. A capacitor can be made variable by providing a means of changing the plate area or the plate separation. A variable capacitor of the type used in the tuning circuits of small radios uses a set of rotating plates which move between a set of stationary plates. The rotor plates are attached to a shaft by which they can rotated between the stator plates, varying the amount of effective plate area of the capacitor. Resonance is particularly important in communication circuits.
Power in an AC Circuit.
In a series RLC circuit, the instantaneous power is
p = iv =
[Im sin
(ωt - φ)][Vm sin ωt] =
ImVm
sin ωt sin (ωt - φ)
Let us find the average power of p over one or more cycles. Using the
trigonometic identity,
sin (ωt - φ) =
sin ωt cos φ -
cos ωt sin φ,
and substituting this into the previous equation, we get
p = ImVm
sin ωt cos φ -
ImVm
cos ωt sin φ.
Now let us take the time average of p over one or more cycles, noting
that Im, Vm, φ and ω are
constants. The time average of the first term on the right involves the
average value of sin ωt which is 1/2. The time average
of the second term on the right is identically zero, because
sin ωt cos ωt =
(1/2)sin 2ωt, whose average value is zero.
Therefore, the aveage power is
Pav = (1/2)ImVm
cos φ.
This can be expressed in terms of the rms voltage and the rms
current defined by equations (8) and (9) above. Thus we get
Pav = IrmsVrms
cos φ,
where the quantity cos φ is called the power factor.
The maximum voltage drop across the resistor is
VR = Im cos φ =
ImR, or
cos φ = ImR/Vm.
Using this expression for cos φ and equations (8) and (9),
we get an equivalent expression for the average power:
Pav = Irms2R.
The average power delivered by the generator to a series RLC circuit is
dissipated as heat in the resistor. There is no power loss in an ideal
inductor or capacitor.
The rms current (or current amplitude) for a
series RLC circuit is
Irms = Vrms/√[R2 +
(XL - XC)2],
where V is the rms applied voltage.
The Transformer and Power Tranmission.
A transformer is a device designed to raise (or lower) an ac voltage and
current without causing an appreciable change in the product of the current and
voltage, IV. In its simplest form, it consists of a primary coil of
N1 turns and a secondary coil of N2
turns, both wound on a common soft iron core. When a voltage
V1 is applied to the primary, the voltage
V2 across the secondary is given by
V2 =
(N2/N1)V1.
When the N2 is greater than N1, the
output voltage V2 will be greater than the input
voltage V1. The transformer is referred to as
step-up transformer. When the N2 is less than
N1, the output voltage V2 will be
less than the input voltage V1. The transformer is
referred to as step-down transformer.
An ideal transformer is one in which the energy losses in the
transformer windings and core can be neglected. In an ideal transformer,
the power supplied by the generator I1V1
is equal to the power in the secondary circuit,
I2V2. That is,
I1V1 =
I2V2.
In an ideal transformer, the power delivered by the generator must equal
the power dissipated at the load. If a load resistor R is connected
across the secondary coil, this means that
I1V1 =
I2V2 =
V22/R.
In a real transformer, the power in the secondary is typically between
90% and 99% of the primary power. The energy losses are due mainly to
hysteresis losses in the transformer core, and thermal energy losses
from currents induced in the core and the coil winding themselves.
Power losses due to hysteresis occur because the core is magnetized
cyclically.
Resistance, Inductance, and Capacitance in Parallel.
An A.C. parallel circuit is defined by the characteristic that
The same voltage occurs across all parallel branches.
Thus in preparing a phasor diagram for any parallel circuit, the common
voltage is used as the reference phasor. If we are given the numerical
value of this voltage, then the currents in the individual branches can
be determined by Ohm's law. Since
IR = (E∠0°)/(R∠0°),
then IR is in phase with the reference phasor.
Since
IL =
(E∠0°)/(XL∠+90°),
then IL lags the reference voltage by 90°.
Since
IC =
(E∠0°)/(XC∠-90°),
then IC leads the reference voltage by 90°.
The total current in a parallel circuit then becomes the vector sum of
branch currents. That is, in complex notation,
IT =
IR - jIL + jIC =
IR -
j(IL - IC). (38)
Converting this equation to polar coordinates, we get
IT = √(IR2 +
IX2)
∠tan-1(IX/IR),
where IX = IL - IC is
called the net reactive current. Let us now determine the equivalent
impedance of the parallel circuit by using Ohm's law for ac circuits,
Ze =
E/IT. (39)
This method for solving for equivalent impedance of a parallel ac circuit
is called the total current method. Even if the exact value of the
applied emf is not known, any convenient value may be assumed to solve for the
calculation of equivalent impedance.
First step. Calculate the value of the impedances, if they are not known,
from the frequency and the value of the inductance L and capacitance
C.
XL = ωL = 2πfL, and
XC = 1/ωC = 1/2πfC.
Second step. Assuming a convenient value of the applied emf, compute
the value the current in each branch by one of the following formulas.
IR = E/R,
IL = E/XL,
IC = E/XC,
Third Step. Using equation (38), compute the total current I.
Fourth Step. Using equation (39), compute the magnitude of the equivalent
impedance.
Fifth step. Calculate the phase angle φ between the total current
and voltage from
φ = arc tan[(IX)/(IR)].
Another method computing the equivalent impedance, which does not require
the computation of the total current, makes use of the quantities called
conductance and admittance. These quantities are the reciprocal of
the resistance and impedance, respectively. Conductance is a measure
of ability of a circuit of pure resistance to pass electric current and is
the reciprocal of resistance; that is,
G = 1/R,
where G is the symbol of conductance and is measured in mhos.
Admittance is a measure of the over-all ability of ac circuit to pass
an electric current and is the reciprocal of the impedance of an ac circuit;
that is,
Y = 1/Z.
where Y is the symbol of admittance and is measured in
mhos.
Equation (38) can be written as
E/Z = E/R -
j[(E/XL) - (E/XC)].
And since the voltage across each component in a simple parallel circuit
is the same, then voltage can be divided out of the equation and it becomes
1/Z = 1/R -
j[(1/XL) - (1/XC)], or
Y = G -
j[BL - BC],
where is BL and BC are the reciprocal of
the inductive reactance and capacitive reactance, respectively, and is called
susceptance. Susceptance is the ability of a pure inductance or
pure capacitance to pass an alternating current. Note that when a vector
quantity with a +90° angle is divided into 1∠0°, the quotient has
a -90° angle and vice versa. Therefore, although inductive reactance is a
+j quantity, inductive susceptance is a -j quantity. Similarly,
capacitive susceptance is a +j quantity. Admittance can be expressed
in polar coordinates as
Y =
√(G2 +
B2)∠arc tan(B/G),
where B = BC - BL and
is called net equivalent susceptance.
This method for solving for equivalent impedance of a parallel ac circuit
is called the admittance method. The following are the steps of
this method.
First step. Convert all resistances R's to conductances G's
and sum all the conductances.
Second step. Convert all inductive reactances XL to
inductive susceptances BL and sum all the inductive
susceptances obtaining BL.
Third step. Convert all capacitive reactances XC to
capacitive susceptances BC and sum all the capacitive
susceptances obtaining BC.
Fourth step. Calculate the net equivalent susceptance B by
combining the sums of inductive and capacitive susceptances. The inductive
susceptances BL are considered negative.
Fifth step. Calculate the magnitude of the admittance Y from
Y = √(G2 + B2),
and, if needed, the magnitude of total impediance Z using
Z = 1/Y.
Sixth step. Calculate the phase angle φ between the total current and
voltage from
φ = arc tan(B/G).
Parallel Resonance.
When inductance L and capacitance C are in parallel and the
inductive reactance XL is equal to the capacitive reactance
XC, the parallel circuit is in resonance, and the
reactive branch currents, IL and IC, are
equal and opposite, canceling each other to produce a minimum current in the
main line. Since the line current is minimum, the impedance is maximum.
These relations are based on the resistance Rs in series
with the inductance, being very small compared to XL at
resonance.
Minimum Line Current at Parallel Resonance.
Since this is a parallel ac circuit, the capacitive current leads by 90°
while the inductive current lags by 90°, compared with the reference
angle of the generator voltage, which is applied across the parallel branches.
Therefore, the opposite currents are 180° out of phase, canceling each
other in the main line. The net current I in the line is, then, the
difference between the currents in the branches. As the frequency increases
toward resonance, the capacitive branch current increases because of the
lower value of XC, while the inductive branch current
decreases with the higher value of XL. As a result,
there is less net line current as the two branch currents become nearly
equal. At the resonant frequency, both reactance are equal and the branch
currents are equal, canceling each other completely. Above the resonant
frequency, there is more current in the capacitive branch than in the
inductive branch and the net line current increases above the minimum
value at resonance.
The in-phase current due to Rs in the inductive branch can be ignored off resonance because it is so small compared with the reactive line current. But at the resonant frequency, when the reactive currents cancel, the resistive component is the entire line current. Its value at resonance is small and is the minimum value of the line current at parallel resonance.
Maximum Line Impedance at Parallel Resonance.
The minimum line current resulting from parallel resonance is uselful
because it corresponds to maximum impedance in the line across the
ac generator. Therefore, an impedance that is high value for just one
frequency but low impedance at other frequencies, either below or
above resonance, can be obtained by using a parallel LC circuit
at the desired frequency. This is another way of selecting one frequency
by resonance. The response curve of line impediance versus frequency
shows how the impedance rises to a maximum for parallel resonance.
The total impedance of the parallel ac circuit is calculated by dividing
the generator voltage by the total line current. That is,
ZT = E/IT.
If a meter is inserted in series with the main line to indicate the total
line current IT, it will dip sharply to the minimum value
of the line current at the resonant frequency. With the minimum current in
the line, the impedance across the line is maximum at the resonant frequency.
The maximum impedance at parallel resonance corresponds to a high value
of resistance, without reactance, since the line current is then
resistive with zero phase angle.