13.5 x ---- = --- and solve for x: x = (13.5)(8) = 108.0 grams. 1 8Thus the gram equivalent weight of silver is 108.0 grams.
CANNIZZARO'S METHOD OF MOLECULAR FORMULA DETERMINATION ------------------------------------------------------------------------ | | 1 | 2 | 3 | 4 | | | Density, | Percentage | Product | Values in 3 | | |grams per | of element | of values | divided by | | Substance | liter | by weight | in 1 and 2 | least value | ------------------------------------------------------------------------ | A. Hydrogen and its gaseous compounds | ------------------------------------------------------------------------ | Hydrogen | 0.0659 | 100.00 | 0.0659 | 2 | | Hydrogen chloride | 1.19 | 2.76 | 0.0329 | 1 | | Water | 0.589 | 11.2 | 0.0659 | 2 | | Ammonia | 0.557 | 17.7 | 0.0986 | 3 | | Methane | 0.524 | 25.1 | 0.132 | 4 | ------------------------------------------------------------------------ | B. Oxygen and its gaseous compounds | ------------------------------------------------------------------------ | Oxygen | 1.05 | 100.00 | 1.05 | 2 | | Water | 0.589 | 88.8 | 0.523 | 1 | | Sulfur dioxide | 2.09 | 50.0 | 1.05 | 2 | | Carbon monoxide | 0.916 | 57.1 | 0.523 | 1 | | Carbon dioxide | 1.44 | 72.7 | 1.05 | 2 | ------------------------------------------------------------------------ | C. Chlorine and its gaseous compounds | ------------------------------------------------------------------------ | Chlorine | 2.32 | 100.0 | 2.32 | 2 | | Hydrogen chloride | 1.19 | 97.2 | 1.16 | 1 | | Chloroform | 3.90 | 89.1 | 3.48 | 3 | | Methylene chloride| 2.78 | 83.5 | 2.32 | 2 | | Carbon | | | | | | Tetrachloride | 5.03 | 92.2 | 4.64 | 4 | ------------------------------------------------------------------------All gas densities in this table are given for 100°C and one atmosphere pressure.
How did Cannizzaro explain these striking numerical data? First, he argued, we must accept the truth of Avogadro's Hypothesis that equal volumes of gases contain equal number of particles. Hence, in comparing densities of gases we are comparing the weights of equal number of molecules. Then when the density of a gas containing a certain element is multiplied by its weight percentage of that element in that gas, the result is the weight of that element per unit volume. The numbers in column 3 of Part A thus represent the weights of hydrogen present in a fixed number of molecules. Now if we compare these weights in a series of substances that contain that element, we should expect them to be different because the number of atoms of that element should vary from substance to substance. And these weights should be integer multiples of some smallest weight, since the atoms of the element in different substances are in integer ratio to each other and to one atom in the substance containing one atom per molecule. Then dividing each weight in column 3 by the smallest weight in column 3 should give us the number of atoms present in one molecule of each substance. Those are the integers in column 4.
This data and Cannizzario's interpretation of it give a confirmation of the second part of Avogadro's Hypothesis that the molecules of gaseous elements may contain more than one atom of the element. In the table in Part A the weight of hydrogen in one liter of elemental hydrogen gas is exactly twice the least weight, that of hydrogen chloride. Thus hydrogen gas does not consist of individual atoms, but of molecules each containing two atoms. And from the results in Parts B and C, we can conclude that oxygen and clorine also consists of diatomic molecules. Cannizzaro's method had at long last provided a means to establish the number of atoms in the molecules of gaseous substances. The smallest physical particle, the molecule, and the smallest chemical unit, the atom, of an element are not necessarily identical.
Hydrogen: 2 × 1.008 = 2.016 Oxygen: 1 × 16.000 = 16.000 -------- 18.016 = molecular weight of water.